z^2-2z-48=(z-10)(z+0)

Solution for z^2-2z-48=(z-10)(z+0) equation:

Simplifying
z2 + -2z + -48 = (z + -10)(z + 0)

Reorder the terms:
-48 + -2z + z2 = (z + -10)(z + 0)

Reorder the terms:
-48 + -2z + z2 = (-10 + z)(z + 0)

Reorder the terms:
-48 + -2z + z2 = (-10 + z)(0 + z)
Remove the zero:
-48 + -2z + z2 = (-10 + z)(z)

Reorder the terms for easier multiplication:
-48 + -2z + z2 = z(-10 + z)
-48 + -2z + z2 = (-10 * z + z * z)
-48 + -2z + z2 = (-10z + z2)

Add '-1z2' to each side of the equation.
-48 + -2z + z2 + -1z2 = -10z + z2 + -1z2

Combine like terms: z2 + -1z2 = 0
-48 + -2z + 0 = -10z + z2 + -1z2
-48 + -2z = -10z + z2 + -1z2

Combine like terms: z2 + -1z2 = 0
-48 + -2z = -10z + 0
-48 + -2z = -10z

Solving
-48 + -2z = -10z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '10z' to each side of the equation.
-48 + -2z + 10z = -10z + 10z

Combine like terms: -2z + 10z = 8z
-48 + 8z = -10z + 10z

Combine like terms: -10z + 10z = 0
-48 + 8z = 0

Add '48' to each side of the equation.
-48 + 48 + 8z = 0 + 48

Combine like terms: -48 + 48 = 0
0 + 8z = 0 + 48
8z = 0 + 48

Combine like terms: 0 + 48 = 48
8z = 48

Divide each side by '8'.
z = 6

Simplifying
z = 6